0=16t^2-41.56t

Solution for 0=16t^2-41.56t equation:

0=16t^2-41.56t

We move all terms to the left:

0-(16t^2-41.56t)=0

We add all the numbers together, and all the variables

-(16t^2-41.56t)=0

We get rid of parentheses

-16t^2+41.56t=0

a = -16; b = 41.56; c = 0;
Δ = b2-4ac
Δ = 41.562-4·(-16)·0
Δ = 1727.2336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(41.56)-\sqrt{1727.2336}}{2*-16}=\frac{-41.56-\sqrt{1727.2336}}{-32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(41.56)+\sqrt{1727.2336}}{2*-16}=\frac{-41.56+\sqrt{1727.2336}}{-32}
$